Java调用百度地图API

本实战代码将使用百度地图的接口来实现以下功能：

  1.确定输入地址的坐标

  2.两个坐标的距离

其他的话，还要使用百度账户申请相关的api，具体见：

http://lbsyun.baidu.com/index.php?title=webapi

示例代码：

1import com.alibaba.fastjson.JSON;
2import com.google.common.collect.ImmutableMap;
3import org.apache.commons.lang3.StringUtils;
4import org.apache.http.client.fluent.Request;
5import org.slf4j.Logger;
6import org.slf4j.LoggerFactory;
7import org.springframework.stereotype.Service;
8
9import java.io.IOException;
10import java.util.Map;
11
12/**
13 * 百度地图api接口调用
14 */
15@Service("geocodingService")
16@Transactional
17public class GeocodingService {
18
19    private static final Logger LOG = LoggerFactory.getLogger(GeocodingService.class);
20
21    private static final Double PI = Math.PI;
22
23    private static final Double PK = 180 / PI;
24
25    private static final String MAP_URL= "http://api.map.baidu.com/geocoder/v2/?ak=4rcKAZKG9OIl0wDkICSLx8BA&output=json&address=";
26
27    /**
28     * 根据地址获取经纬度
29     * @param address
30     * @return
31     */
32    private Map<String,Double> getLatAndLngByAddress(String address){
33        Map<String,Double> poiMap = null;
34        String result = null;
35        try {
36            result = Request.Get(MAP_URL+ address)
37                    .connectTimeout(1000).socketTimeout(1000)
38                    .execute().returnContent().asString();
39        } catch (IOException e) {
40            LOG.error("调用百度地图API获取{}的经纬度，抛错{}",address,e);
41        }
42        if (StringUtils.isNotBlank(result) && "0".equals(JSON.parseObject(result).get("status") + "")){
43            String lat = result.substring(result.indexOf("\"lat\":")
44                    + ("\"lat\":").length(), result.indexOf("},\"precise\""));
45            String lng = result.substring(result.indexOf("\"lng\":")
46                    + ("\"lng\":").length(), result.indexOf(",\"lat\""));
47            poiMap = ImmutableMap.of("lat",Double.parseDouble(lat),"lng",Double.parseDouble(lng));
48        }
49        return poiMap;
50    }
51
52    /**
53     * 计算两个地址的距离（米）
54     * @param address
55     * @param otherAddress
56     * @return
57     */
58    public Double getDistanceFromTwoPlaces(String address,String otherAddress){
59        Double distance = null;
60        if (StringUtils.isNotBlank(address) && StringUtils.isNotBlank(otherAddress)){
61            address = address.trim();
62            otherAddress = otherAddress.trim();
63            if (address.equals(otherAddress)){
64                return 0.0d;
65            }
66            Map pointA = getLatAndLngByAddress(address);
67            Map pointB = getLatAndLngByAddress(otherAddress);
68            distance = getDistanceFromTwoPoints(pointA,pointB);
69        }
70        return distance;
71    }
72
73    /**
74     * 获取两个经纬度之间的距离（单位：米）
75     * @param pointA
76     * @param pointB
77     * @return
78     */
79    private Double getDistanceFromTwoPoints(Map pointA, Map pointB) {
80        Double distance = null;
81        if (pointA != null && !pointA.isEmpty() && pointB != null && !pointB.isEmpty()){
82            double lat_a = (double) pointA.get("lat");
83            double lng_a = (double) pointA.get("lng");
84            double lat_b = (double) pointB.get("lat");
85            double lng_b = (double) pointB.get("lng");
86
87            if (lat_a == lat_b && lng_a == lng_b){
88                return 0.0d;
89            }
90
91            double t1 = Math.cos(lat_a / PK) * Math.cos(lng_a / PK) * Math.cos(lat_b / PK) * Math.cos(lng_b / PK);
92            double t2 = Math.cos(lat_a / PK) * Math.sin(lng_a / PK) * Math.cos(lat_b / PK) * Math.sin(lng_b / PK);
93            double t3 = Math.sin(lat_a / PK) * Math.sin(lat_b / PK);
94
95            double tt = Math.acos(t1 + t2 + t3);
96            distance = 6366000 * tt;
97        }
98        return distance;
99    }
100}

http://blog.csdn.net/u013142781/article/details/47085369