java中实现对list的模糊查询

比如我有下面这样一个List，里面存放的是多个Employee对象。然后我想对这个List进行按照Employee对象的名字进行模糊查询。有什么好的解决方案么？
比如我输入的查询条件为“wang”，那么应该返回只包含employee1的List列表。

1List list = new ArrayList();
2Employee employee1 = new Employee();
3employee1.setName("wangqiang");
4employee1.setAge(30);
5list.add(employee1);
6Employee employee2 = new Employee();
7employee2.setName("lisi");
8list.add(employee2);
9employee2.setAge(25);

方式一：

1public List search(String name,List list){
2   List results = new ArrayList();
3   Pattern pattern = Pattern.compile(name);
4   for(int i=0; i < list.size(); i++){
5      Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
6      if(matcher.matches()){
7         results.add(list.get(i));
8      }
9   }
10   return results;
11}

上面那个是大小写敏感的，如果要求大小写不敏感，改成：
Pattern pattern = Pattern.compile(name,Pattern.CASE_INSENSITIVE);

并且上面那个是精确查询，如果要模糊匹配，matcher.find()即可以进行模糊匹配。

1public List search(String name,List list){
2   List results = new ArrayList();
3   Pattern pattern = Pattern.compile(name);
4   for(int i=0; i < list.size(); i++){
5      Matcher matcher = pattern.matcher(((Employee)list.get(i)).getName());
6      if(matcher.find()){
7         results.add(list.get(i));
8      }
9   }
10   return results;
11}

 方式二：

1public class ListLike {
2
3//定义员工类
4public class Employee {
5private String name;
6private int age;
7public int getAge() {
8return age;
9}
10public void setAge(int age) {
11this.age = age;
12}
13public String getName() {
14return name;
15}
16public void setName(String name) {
17this.name = name;
18}
19}
20
21public List list=new ArrayList();
22
23//增加员工
24public List addList(String name,int age){
25Employee employee1 = new Employee();
26employee1.setName(name);
27employee1.setAge(age);
28list.add(employee1);
29return list;
30}
31
32//显示所有员工
33public void ShowList(){
34for(int i=0;i<list.size();i++){
35System.out.println(((Employee)(list.get(i))).getName()+" "+((Employee)(list.get(i))).getAge());
36}
37}
38
39//模糊查询
40public List likeString(String likename){
41for(int i=0;i<list.size();i++){
42if(((Employee)(list.get(i))).getName().indexOf(likename)<=-1)
43list.remove(i);
44}
45return list;
46
47}
48
49public static void main(String arg[]){
50ListLike ll=new ListLike();
51ll.addList("wuxiao",13);
52ll.addList("wangwang",11);
53ll.addList("wanghua",12);
54ll.addList("xiaowang",13);
55ll.addList("xiaoxiao",13);
56
57ll.likeString("wang");
58ll.ShowList();
59
60
61}
62
63}