组合使用map 和find重组数组对象

需求：有两个均是数组对象结构的数组，如下：

1//第一个数组对象结构如下：   arr1数组长度大于arr2
2arr1=[
3  {adCode:"12340",adName:'河南省'},
4  {adCode:"12341",adName:'山东省'},
5  {adCode:"12342",adName:'广东省'},
6  {adCode:"12343",adName:'上海市'},
7  {adCode:"12344",adName:'安徽省'},
8]

1//第二个数组对象结构如下：
2arr2=[
3  {adCode:'12342',adValue:"98"},
4  {adCode:'12340',adValue:"48"},
5  {adCode:'12341',adValue:"90"},
6]

由上面的数据结构可以看出，若想获得如下数据结构：

1arr3=[
2  {adName:"河南省",adValue:"48"}
3]

则可进行如下操作：

1const arr = arr1.map((v)=>{
2    const newResult = arr2.find((item)=>v.adCode ===item.adCode);
3    return {adName:v.adName,adValue:newResult.adValue}
4})

若arr2数组结构如下：

1arr2=[
2  {adCode:'12342',adValue:"98"},
3  {adCode:'12340',adValue:undefined},
4  {adCode:'12341',adValue:"90"},
5  {adCode:'12344',adValue:"40"},
6  {adCode:'12343',adValue:undefined},
7]

则操作如下：

1const arr = arr1.map((v)=>{
2     //adValue值为undefined时,不纳入新数组arr中
3    const newResult = arr2.find((item)=>v.adCode ===item.adCode) || {};
4    return {adName:v.adName,adValue:newResult.adValue}
5})